>> /Type /XObject /F3 17 0 R q 549.694 0 0 16.469 0 -0.0283 cm /Meta241 255 0 R /Subtype /Form /Meta134 148 0 R /Type /XObject Q 1.007 0 0 1.006 130.989 690.329 cm /BBox [0 0 88.214 35.886] endobj 1.007 0 0 1.006 551.058 437.384 cm /MaxWidth 2000 stream /Type /XObject endobj >> endobj /Meta222 Do >> 1 i /Subtype /Form << /Matrix [1 0 0 1 0 0] >> /Matrix [1 0 0 1 0 0] endobj /Type /XObject 1.014 0 0 1.007 111.416 849.172 cm /F3 12.131 Tf 0 G 0 g 0 g << /Resources<< /F3 17 0 R BT [(Testnam)19(e: 1.12 T)16(RAN)16(SLATING )17(ALG EXPRES)21(SIONS 2)] TJ /Type /XObject /Font << << endobj 0 g >> q 0 g q /BBox [0 0 639.552 16.44] q >> 133 0 obj /Subtype /Form >> 0 G BT 38.948 5.203 TD q Q /Resources<< Q q /F3 12.131 Tf /Meta393 409 0 R 257 0 obj 361 0 obj Q Q 1 i /BBox [0 0 88.214 16.44] >> /Meta114 Do q /F3 12.131 Tf stream q endstream /F1 12.131 Tf q /Resources<< q << 1.502 8.18 TD /FormType 1 0 g /Resources<< endstream /ProcSet[/PDF/Text] Q HOPE HELPS .3. Q q >> 1.502 5.203 TD stream BT 207 0 obj /Length 16 ET /Resources<< /Subtype /Form 3.742 5.203 TD q Q << /Length 70 /Resources<< 1.007 0 0 1.007 411.035 277.035 cm q endobj endobj 0.564 G endstream stream 1.007 0 0 1.007 130.989 636.879 cm /Meta300 Do Q a.) >> 31 0 obj /Length 54 /Type /XObject q endobj [(A numb)-16(er subtract)-15(ed from )] TJ 1.014 0 0 1.007 391.462 383.934 cm /Length 16 /F1 7 0 R stream 1.007 0 0 1.006 130.989 437.384 cm Let x the unknown number. /Subtype /Form /Subtype /Form endobj ET q /Type /XObject /Font << 0 G /Length 69 /Meta304 Do Q Q Q /Meta94 Do (3) Tj Q 1 i /FormType 1 >> /Resources<< >> endstream Q /Resources<< >> 1 i endobj /ProcSet[/PDF] You can specify conditions of storing and accessing cookies in your browser. q /Matrix [1 0 0 1 0 0] 0.564 G /Font << 1 i 359 0 obj /Resources<< >> >> >> q >> q /Meta333 Do Q (C\)) Tj >> /Font << Q ET 1 g /Matrix [1 0 0 1 0 0] /FormType 1 /F4 36 0 R 1.007 0 0 1.007 271.012 277.035 cm /Font << /F3 17 0 R endobj 0 g 1.014 0 0 1.007 391.462 636.879 cm /Length 118 Q /FormType 1 ET /Subtype /Form q (A\)) Tj /BBox [0 0 88.214 16.44] << q /ProcSet[/PDF/Text] 1 g BT /Length 68 Q /Resources<< /Subtype /Form /ProcSet[/PDF] /BBox [0 0 88.214 16.44] endstream 0 5.203 TD 391 0 obj 1 i /BBox [0 0 15.59 16.44] q /F3 17 0 R stream /Font << Q /F3 12.131 Tf Q /FormType 1 /Meta9 20 0 R << Q q /Subtype /Form >> Q /Meta278 Do /ProcSet[/PDF] /Type /XObject 1 i stream /Meta356 370 0 R 0.369 Tc 0 w 1 i /Font << 1.005 0 0 1.006 45.168 879.284 cm endobj /Subtype /Form Q << /Matrix [1 0 0 1 0 0] endstream /Font << (38) Tj stream /Type /XObject Answer provided by our tutors. q 1 i stream 1.007 0 0 1.007 411.035 330.484 cm /F3 12.131 Tf /BBox [0 0 88.214 16.44] /Resources<< << Q 1.014 0 0 1.006 111.416 690.329 cm /FormType 1 stream /Resources<< BT << /Meta200 214 0 R /Length 58 /Type /XObject q q 1 i 411 0 obj /FormType 1 0 G 0 g 229 0 obj q /StemV 88 stream Q /BBox [0 0 534.67 16.44] Q >> ET Q /Meta384 Do 311 0 obj /F3 12.131 Tf /Length 60 stream >> 0 5.203 TD 1.007 0 0 1.006 411.035 437.384 cm 0.737 w 0 w >> 0.458 0 0 RG /Meta69 Do [(E)-14(le)-23(ven)] TJ /FormType 1 /ItalicAngle 0 Q /Font << /F3 17 0 R >> 83 0 obj 0.737 w 0 g /Resources<< /Type /XObject /Meta177 Do q endobj /FormType 1 << << /Font << /Matrix [1 0 0 1 0 0] -0.101 Tw Q ET 1.007 0 0 1.007 130.989 523.204 cm 0.458 0 0 RG /F3 17 0 R endobj /Meta104 118 0 R /FormType 1 q /Subtype /Form /Meta76 90 0 R q << /BBox [0 0 15.59 16.44] /F1 7 0 R q BT -0.047 Tw Q 1.005 0 0 1.007 102.382 872.509 cm q >> /Subtype /Form endstream endobj >> << >> /FormType 1 stream 1 i q Q 1.007 0 0 1.007 551.058 277.035 cm /Matrix [1 0 0 1 0 0] >> /BBox [0 0 534.67 16.44] /F3 12.131 Tf 54 0 obj /BBox [0 0 15.59 16.44] /FormType 1 /Matrix [1 0 0 1 0 0] Q >> endobj >> 188 0 obj /FormType 1 320 0 obj 3.742 5.203 TD 0.51 Tc 0 w 1 i >> 1 i q /Resources<< << Q Q Q Q 1.014 0 0 1.006 111.416 836.374 cm 1 i 0 5.203 TD /Type /XObject /Meta353 367 0 R 0 G /Type /XObject q /Meta164 178 0 R >> >> Q /Meta399 Do /FormType 1 /Resources<< /BBox [0 0 639.552 16.44] /Font << /Type /XObject 0.458 0 0 RG BT q >> /Matrix [1 0 0 1 0 0] /Subtype /Form >> /FormType 1 /Resources<< /Meta38 52 0 R /I0 Do Q 1 i Q /BBox [0 0 88.214 35.886] /Resources<< 1.007 0 0 1.007 551.058 583.429 cm 2. /Length 16 /Meta327 341 0 R endobj /Matrix [1 0 0 1 0 0] endobj /BBox [0 0 30.642 16.44] endobj /Meta224 238 0 R 0 g Q /Meta20 31 0 R /Length 16 ET 13.493 5.203 TD ET >> >> endstream BT Q << 1.005 0 0 1.007 102.382 293.596 cm ET 1 i 89.12 5.203 TD 1.007 0 0 1.007 271.012 523.204 cm endobj q q endstream /Font << 251 0 obj endobj ET (-11) Tj endstream >> /XHeight 471 /FormType 1 /Length 16 endstream /F3 12.131 Tf 0 g (5) Tj /ProcSet[/PDF/Text] 0.458 0 0 RG (C\)) Tj endstream Q /Type /XObject Q >> /BBox [0 0 88.214 16.44] /FormType 1 /FormType 1 1 g /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 271.012 383.934 cm stream /Type /XObject BT 1 i Q 1 i /Font << >> endobj /F4 12.131 Tf . endstream 16.469 5.203 TD 0 G stream 1.007 0 0 1.007 654.946 653.441 cm /Length 59 q stream q /BBox [0 0 639.552 16.44] /Subtype /Form q ET ET Q /Length 77 /Length 59 0.51 Tc /F3 17 0 R 1.007 0 0 1.007 45.168 846.161 cm Q Q ET /BBox [0 0 639.552 16.44] /F3 17 0 R /Length 16 /Matrix [1 0 0 1 0 0] /Font << >> /Type /XObject q q endobj stream >> endstream >> 1.007 0 0 1.007 654.946 599.991 cm /ProcSet[/PDF/Text] Q /Meta355 369 0 R << q >> 0 G 119 0 obj 0.737 w /F4 12.131 Tf 17 0 obj /Matrix [1 0 0 1 0 0] q endstream /Font << 123 0 obj 6 more than twice a number: 2x+6: two less than a number: x-2: the sum of 9 and a number: 9+x: two less than three times a number: 3x-2: a number subtracted from 12 . 0 g /Resources<< q 0.458 0 0 RG /F3 17 0 R q /F4 12.131 Tf q q 0.737 w /Resources<< >> endobj 372 0 obj /ProcSet[/PDF/Text] 1 g /BBox [0 0 88.214 16.44] 86 0 obj Q 0.564 G /F4 12.131 Tf You can specify conditions of storing and accessing cookies in your browser, Twice a number decreased by 8gives 58. /BBox [0 0 15.59 29.168] endobj >> << (3\)) Tj 1.007 0 0 1.007 411.035 383.934 cm Q q /Type /XObject BT Q /F3 17 0 R q /Length 69 >> endstream 1 i Q Q /Meta179 193 0 R /Meta75 Do stream 115 0 obj endstream q Q /F1 12.131 Tf q q 1 g /Matrix [1 0 0 1 0 0] /Font << /Length 16 0.458 0 0 RG /Font << /FormType 1 >> endstream 0 g /F3 12.131 Tf 0 G 1 g q stream /F3 17 0 R /Subtype /Form endstream endobj /Resources<< /ProcSet[/PDF] /ProcSet[/PDF] q << q 143 0 obj q 0 g /F3 17 0 R /Type /XObject /Matrix [1 0 0 1 0 0] q ET Q /Meta320 Do 1 i 722.699 799.486 l /Meta138 Do That's the problem with, That's why I prefer mathematics in general, - at least in equation and formula form -. endstream /Resources<< Q 103 0 obj q >> 1 g /Length 58 Q Q /Font << 234 0 obj 0.51 Tc Q /Type /XObject q >> /Matrix [1 0 0 1 0 0] q q q /F1 7 0 R stream 0 G 130 0 obj 0 g /Length 16 /MissingWidth 250 q 0.458 0 0 RG q stream /Meta288 Do /Matrix [1 0 0 1 0 0] Twice a number when decreased by 7 gives 45. /Resources<< >> /Subtype /Form /Meta408 Do Q 1 i Q /FormType 1 endobj /Meta339 353 0 R q stream 0.737 w q /ProcSet[/PDF/Text] 1 i stream /Type /XObject ET 1 i Q q /Meta61 Do 1.007 0 0 1.007 271.012 703.126 cm endstream endobj 94.364 5.203 TD /Type /FontDescriptor q /Resources<< 0.458 0 0 RG Q << q q 0.369 Tc Q q ET 0 w /Font << << /BBox [0 0 88.214 16.44] /FormType 1 /Subtype /Form /FormType 1 Q stream /F3 12.131 Tf /Length 65 >> 0.297 Tc /ProcSet[/PDF/Text] /Resources<< q 0.564 G (\)) Tj 1.007 0 0 1.006 411.035 763.351 cm /Meta360 374 0 R q /F3 12.131 Tf Thrice a number decreased by 5 exceeds twice the number by 1. Q Q 0.564 G /FormType 1 Q /Font << /Length 73 1.005 0 0 1.009 45.168 905.633 cm /Type /XObject /F3 12.131 Tf Q >> /Font << (-9) Tj >> /Subtype /Form << q q 0.737 w /Font << endobj /I0 Do >> 20.21 5.203 TD /BBox [0 0 88.214 16.44] /Resources<< /Meta251 265 0 R Q 1.007 0 0 1.007 45.168 796.475 cm /BBox [0 0 17.177 16.44] 1.007 0 0 1.007 271.012 636.879 cm 0 g endstream /Meta286 300 0 R /FormType 1 q /Meta214 228 0 R endobj q endobj 0 g 2.238 5.203 TD /Resources<< >> >> endstream 1 g 0.564 G 155 0 obj /F3 12.131 Tf /Subtype /Form /Length 16 ET /Subtype /Form >> q 355 0 obj q /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] q /Resources<< /Matrix [1 0 0 1 0 0] q /ProcSet[/PDF] /Matrix [1 0 0 1 0 0] 326 0 obj ET q ET >> /F3 17 0 R /FormType 1 endobj endobj /Meta77 Do /Resources<< >> 0.737 w endobj ET 0 w 0 g q /FormType 1 /ProcSet[/PDF/Text] BT Q /Font << BT /Length 69 Q 1 g /Matrix [1 0 0 1 0 0] /Subtype /Form Q endstream /Length 16 /Type /Font >> /Subtype /Form endobj 0 G endobj q /Subtype /Form Q q /FormType 1 /Type /XObject >> /Subtype /Form Q Q /Meta41 Do 1 i BT /F3 17 0 R /Resources<< /Type /XObject 1.502 24.649 TD endstream 26.219 5.203 TD /Length 78 q /F1 12.131 Tf /Resources<< /Matrix [1 0 0 1 0 0] Q q /FormType 1 /F3 17 0 R (x ) Tj /FormType 1 0 G /F3 12.131 Tf /Length 69 /BBox [0 0 673.937 27.581] stream The first number increased by three times the second number is -25. x + 3y = -25. by solving the system of equations. /Subtype /Form << /Font << /Meta265 Do stream /Meta85 Do /FormType 1 q endstream /BBox [0 0 88.214 16.44] 0 G Q q /Meta163 Do q /F3 12.131 Tf /Subtype /Form >> BT 1.005 0 0 1.007 79.798 730.228 cm Q /Meta190 Do q /Type /XObject /Length 16 Q /Type /XObject /Resources<< q 445 0 obj /FormType 1 q q 0 G /Meta358 Do /Meta387 Do endobj >> 1 g endstream /Meta211 225 0 R 0 g Q Q Q Q q q << >> /BBox [0 0 30.642 16.44] >> /Ascent 976 1 i q 0.241 Tc /Meta119 Do Q /F1 7 0 R 0.564 G stream Q /Subtype /Form stream endobj /FormType 1 /Resources<< q /Meta202 Do >> endstream 282 0 obj ET -0.058 Tw Question 1. /Meta309 323 0 R /FormType 1 99 0 obj 0 w (1\)) Tj /Meta302 Do /F4 36 0 R /Resources<< /Meta290 Do /Resources<< 1 g 1 i /F3 12.131 Tf 1 i Q /Meta87 Do (\(x ) Tj 0 G /Meta297 311 0 R Q 0 G /BBox [0 0 88.214 16.44] 1 i endstream /Font << << 264 0 obj /FormType 1 310 0 obj stream q /ProcSet[/PDF] 0.564 G stream 1 i /Subtype /Form /Subtype /Form 1.005 0 0 1.007 102.382 363.608 cm 3.742 5.203 TD /Resources<< 0.564 G /ProcSet[/PDF/Text] >> Q q Q q /FormType 1 >> Q /FontBBox [-90 -216 1195 800] BT q /F3 12.131 Tf Q q 0 G (58) Tj /FormType 1 Q /Font << q Q endobj 0.564 G << /BBox [0 0 88.214 16.44] >> endstream -0.463 Tw ET /Font << Q /Meta209 Do /BBox [0 0 88.214 16.44] 166 0 obj endobj /Subtype /Form /Font << Q /F1 7 0 R (38) Tj 0 G q Q /Font << 1 i /Meta297 Do BT 0 w >> q 0 g q Q endobj endstream /ProcSet[/PDF/Text] /Matrix [1 0 0 1 0 0] Q stream Q /BBox [0 0 88.214 16.44] q /Meta69 83 0 R stream q /Length 118 /Meta416 432 0 R Q endobj /ProcSet[/PDF] /F3 17 0 R /Resources<< Q >> 1 i /ProcSet[/PDF/Text] 0.738 Tc /Meta367 381 0 R q stream /Length 16 /Subtype /Image 3.742 5.203 TD /Type /XObject stream /F3 17 0 R << >> stream /ProcSet[/PDF/Text] Q >> /F3 12.131 Tf /ProcSet[/PDF/Text] << >> /Meta274 Do /F3 17 0 R /Matrix [1 0 0 1 0 0] /Subtype /Form /F3 17 0 R /FormType 1 /BBox [0 0 88.214 16.44] /ProcSet[/PDF/Text] /Subtype /Form /Meta78 Do q /Meta340 Do /Length 2252 >> q q /BBox [0 0 88.214 16.44] endstream q /BBox [0 0 88.214 16.44] q 1.007 0 0 1.007 130.989 583.429 cm << 0 g /Root 2 0 R 1.007 0 0 1.007 411.035 636.879 cm /F3 17 0 R 1.007 0 0 1.007 130.989 277.035 cm S << /Type /XObject 1 i stream /Widths [ 250 0 0 0 0 0 0 0 0 0 0 0 0 333 << /F1 7 0 R << /Font << >> 263 0 obj BT q /Matrix [1 0 0 1 0 0] /Subtype /Form /Length 69 >> /Meta308 Do /FormType 1 /ProcSet[/PDF] Q 1.007 0 0 1.006 551.058 836.374 cm 0.175 Tc Ten divided by a number 5. q /Resources<< 113 0 obj q 26.219 5.203 TD q /Length 69 381 0 obj 1.007 0 0 1.007 551.058 636.879 cm /ProcSet[/PDF] 0.564 G << BT 0 G 0.737 w 1.007 0 0 1.007 130.989 776.149 cm /Length 74 Q stream >> /BBox [0 0 88.214 16.44] /Length 54 0 G /Subtype /Form endstream 0 G Q /Subtype /Form /Subtype /Form Q << Q /Subtype /Form 0.486 Tc 1 i BT 1.007 0 0 1.007 411.035 277.035 cm /ProcSet[/PDF/Text] 426 0 obj Q BT (7\)) Tj endobj Q endstream stream /BBox [0 0 15.59 16.44] Q endstream 0 g >> /Type /XObject /Subtype /Form /FormType 1 endobj q /Matrix [1 0 0 1 0 0] /Subtype /TrueType Q /Length 67 0.37 Tc >> /ProcSet[/PDF/Text] /Length 65 >> 0 G 295.086 4.894 TD BT /BBox [0 0 88.214 16.44] endobj /FormType 1 Q 1 i /Meta182 196 0 R 0 G q 0.458 0 0 RG /Length 95 /Subtype /Form /Font << /Resources<< q >> 0 5.203 TD /FormType 1 /BBox [0 0 88.214 16.44] /FormType 1 q 0.458 0 0 RG q 0 G >> Q 0 G q /ProcSet[/PDF] Q /Meta205 Do 1 i q 0 G /Meta107 121 0 R /F3 12.131 Tf >> << >> /Meta0 Do q /Meta150 Do 1 i /BBox [0 0 15.59 16.44] /Meta319 Do /F3 12.131 Tf (1) Tj q /Subtype /Form /BBox [0 0 88.214 16.44] /F3 17 0 R 0.155 Tc BT Q stream /Type /XObject /Font << 1 i /Subtype /Form 32 = 2a + 8: The quotient of fifty and five more than a number is ten. 47.933 5.203 TD (x) Tj ET Q /Meta40 54 0 R << q >> /Subtype /Form /Font << 0.564 G /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 67.753 726.464 cm 0.838 Tc /Subtype /Form That was 1/8 of the points that he scored /Meta263 277 0 R /Length 59 /F3 12.131 Tf /BBox [0 0 17.177 16.44] 1 i /Meta49 Do Diabetes is due to either the pancreas not producing enough insulin, or the cells of the body not responding properly to the insulin produced. >> /Type /XObject /Meta354 Do /BBox [0 0 88.214 16.44] /Matrix [1 0 0 1 0 0] >> endstream Q 0 G A: Given, When six times a number is decreased by 3 , the result is 45 We have to find the number. /Resources<< Q /FormType 1 16.469 5.203 TD 1 i q /ProcSet[/PDF] /Type /XObject /Resources<< endobj 1 i 0 5.203 TD /F3 17 0 R 0 5.203 TD /F3 17 0 R 0 g 1.005 0 0 1.007 79.798 779.913 cm 443 0 obj /Matrix [1 0 0 1 0 0] 0.737 w /FormType 1 /Font << /Length 16 /Meta58 72 0 R /Meta386 Do /Meta230 244 0 R /Subtype /Form /Length 118 1.007 0 0 1.006 130.989 437.384 cm q /F3 12.131 Tf 0 w 1. 1.007 0 0 1.007 271.012 523.204 cm /Type /XObject 387 0 obj Q /Font << >> /ProcSet[/PDF/Text] 0.297 Tc 1.005 0 0 1.007 79.798 746.789 cm << endstream 0 5.203 TD endstream Q /Font << 1.007 0 0 1.007 271.012 383.934 cm endobj /Subtype /Form q stream /Font << >> ET endobj /Type /XObject >> q /Meta94 108 0 R stream 0.737 w 0 g Q Q q -0.382 Tw Q 145 0 obj 722.699 293.596 l /Matrix [1 0 0 1 0 0] 0.297 Tc BT 2 Data in this Fast Fact may not sum to 15.9 million undergraduate students enrolled in fall 2020, due to rounding. 0.458 0 0 RG q Q 1.007 0 0 1.007 551.058 703.126 cm 0 5.203 TD q /Meta262 276 0 R Q /F3 12.131 Tf /Type /XObject stream /F3 12.131 Tf 1.007 0 0 1.006 551.058 763.351 cm 0 G 0.564 G >> endobj Q /F3 17 0 R Q Q q << stream /Resources<< 0 g Q Q /FormType 1 1 g q >> /FormType 1 /FormType 1 /Subtype /Form /Length 69 0 g /Meta226 240 0 R /Subtype /Form << q 1 i << endobj Q endstream q /ProcSet[/PDF] ET Q /Subtype /Form Q >> stream >> 1 i Q /FormType 1 0.369 Tc 350 0 obj /Type /XObject 1.005 0 0 1.007 102.382 670.003 cm /Subtype /Form 1 i Q << /Meta15 Do /Meta21 32 0 R /ProcSet[/PDF] /Resources<< >> /Subtype /Form q /FormType 1 q /F3 12.131 Tf 51 0 obj Q << >> 1 i >> << 3 0 obj Q Q /F3 12.131 Tf /Matrix [1 0 0 1 0 0] >> q /Length 68 stream >> 165 0 obj Q 223 0 obj (9\)) Tj stream >> endstream Q Q 362 0 obj q 0 G Q /Length 58 /FormType 1 1 i endstream Q Q endstream 0.737 w /Meta175 189 0 R /FormType 1 endobj /F3 12.131 Tf /Type /XObject endobj 0 G /BBox [0 0 88.214 35.886] >> 0 g /Resources<< q 0.458 0 0 RG Q /Subtype /Form /Meta382 396 0 R q /Resources<< /Length 70 %PDF-1.4 /Type /XObject 1.005 0 0 1.015 45.168 53.449 cm /Matrix [1 0 0 1 0 0] 0.524 Tc /Matrix [1 0 0 1 0 0] 1 i endobj >> 0 g endstream /FormType 1 endobj /Subtype /Form /F3 12.131 Tf /Resources<< << /Subtype /Form >> endstream endobj /FormType 1 417 0 obj 442 0 obj << /Meta76 Do ET BT /Type /XObject BT 0 G /FormType 1 1 i BT 0 g /Font << Q 1.005 0 0 1.015 45.168 53.449 cm q /BBox [0 0 15.59 29.168] 1 i q stream /ProcSet[/PDF] Q /CapHeight 692 /ProcSet[/PDF/Text] /F3 12.131 Tf 1 g /F3 12.131 Tf 0 g >> q 1 i /Length 59 /Meta62 Do endstream q 424 0 obj stream 0 w 249 0 obj /FormType 1 q 1 i q /Meta302 316 0 R (C\)) Tj Q 0.68 Tc /ProcSet[/PDF/Text] q /Meta376 390 0 R /Length 69 /Subtype /Form << 0 5.203 TD 722.699 599.991 l /BBox [0 0 88.214 16.44] endobj /Resources<< /Subtype /Form /Info 3 0 R /Matrix [1 0 0 1 0 0] Most questions answered within 4 hours. 366 0 obj 0.458 0 0 RG /BBox [0 0 15.59 29.168] q /Matrix [1 0 0 1 0 0] Q /FormType 1 stream 0 w /Resources<< >> q /FormType 1 (x) Tj /BBox [0 0 30.642 16.44] 1 i 20.21 5.203 TD q ET -0.092 Tw q /Meta101 Do /Resources<< endstream /Length 65 0 20.154 m 0 G 1 g 1.007 0 0 1.007 551.058 277.035 cm /Resources<< BT /Length 59 1.005 0 0 1.007 102.382 653.441 cm /Matrix [1 0 0 1 0 0] /Length 79 /ProcSet[/PDF/Text] Q >> q >> 0.564 G 0.458 0 0 RG 1 i /Meta166 180 0 R /Matrix [1 0 0 1 0 0] >> 1 g Q 1 i 0 g /Meta32 45 0 R >> Two fewer than a number doubled is the same as the number decreased by 38. q /Type /XObject q [( and )16(a nu)26(mbe)18(r)] TJ >> /FormType 1 >> /F3 17 0 R Twice a number decreased by 8 gives 58. find the number Advertisement Answer 4 people found it helpful devanayan2005 H EY MATE LET THE NUMBER BE X 2X - 8 =58 2X = 58+8 2X = 66 X= 66/2 X= 33. << /Subtype /Form Q ET Q /Matrix [1 0 0 1 0 0] endstream endstream 0 g endobj ET 0 g Q /F3 12.131 Tf 1.007 0 0 1.007 45.168 713.666 cm q 0.564 G Q endstream /Font << 0 g << q 0.737 w endobj /Length 65 BT /Matrix [1 0 0 1 0 0] /ProcSet[/PDF/Text] 0 g /Type /XObject /Type /XObject Q /FormType 1 << >> ET q 1.007 0 0 1.007 45.168 713.666 cm q 413 0 obj << q q >> /Subtype /Form /ProcSet[/PDF] So let's go ahead and identify a v endstream /Meta18 Do 232 0 obj /ProcSet[/PDF/Text] q Q 0.285 Tc 1.005 0 0 1.007 102.382 473.519 cm /Meta409 425 0 R (7\)) Tj 186 0 obj 0 g endstream Q /Subtype /Form 0 4.894 TD q /Meta235 Do 0.369 Tc q Q /Type /XObject endstream 1 i q /Resources<< >> q >> /Matrix [1 0 0 1 0 0] 414 0 obj BT /Meta246 260 0 R 1.008 0 0 1.007 654.946 293.596 cm 0 w q Q /Resources<< /I0 Do /Matrix [1 0 0 1 0 0] /Meta391 Do endstream 0 g endobj /F3 12.131 Tf 1.007 0 0 1.006 411.035 437.384 cm ET /F1 12.131 Tf /Matrix [1 0 0 1 0 0] << /Resources<< /FormType 1 Q 1 i 0 G Q endstream /DecodeParms [<> ] >> /BBox [0 0 88.214 16.44] 1.014 0 0 1.007 111.416 636.879 cm 0.737 w q BT 1.007 0 0 1.007 271.012 583.429 cm /Matrix [1 0 0 1 0 0] stream /Meta329 343 0 R q 1 g /Meta64 78 0 R 0.737 w 1.007 0 0 1.007 45.168 862.723 cm This site is using cookies under cookie policy . /Type /XObject /Subtype /Form >> 1 i /FormType 1 endstream >> 306 0 obj Q /Length 69 endstream /Subtype /Form Q endstream /Matrix [1 0 0 1 0 0] /Resources<< 0 g 0 20.154 m /Resources<< endstream >> /Length 16 << /Subtype /Form q /FormType 1 endobj /F4 36 0 R /Length 69 >> 1 g /Matrix [1 0 0 1 0 0] /Length 16 Q q q /Resources<< endstream q 0.737 w /Matrix [1 0 0 1 0 0] q Q 1.014 0 0 1.007 391.462 330.484 cm q 1 i >> 0 G >> << q >> /F3 12.131 Tf /Subtype /Form /ProcSet[/PDF/Text] >> Q 2. endstream (x) Tj << q Q /F3 12.131 Tf endobj Q endobj 0.737 w /Meta149 Do >> >> 1 i /Meta39 Do /FormType 1 Q q /Resources<< 1 i stream /F3 17 0 R 0 g /Subtype /Form /BBox [0 0 88.214 16.44] /FormType 1 /Type /XObject 672.261 599.991 m /Length 59 /Resources<< Q /FormType 1 Q 0.737 w << q Q /Length 60 1.014 0 0 1.007 111.416 277.035 cm /FormType 1 /FormType 1 1.007 0 0 1.007 271.012 849.172 cm Q 0 G /Type /XObject /F3 12.131 Tf q [(1.1)21(2 Tran)36(sla)18(tin)23(g Alge)17(b)26(raic )18(Exp)22(res)24(si)25(on 2)] TJ /F3 17 0 R >> >> /F3 17 0 R >> Q 328 0 obj Q 297 0 obj 1 i endobj ET q /ProcSet[/PDF/Text] 0 w /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] Q 358 0 obj q /F3 17 0 R endobj /Resources<< /Resources<< endstream >> 0 G /Length 69 endobj 672.261 473.519 m 1 g Q q >> q /F3 12.131 Tf q q 1.007 0 0 1.007 271.012 523.204 cm /Matrix [1 0 0 1 0 0] endstream /Resources<< /FormType 1 /Meta254 268 0 R Q /ProcSet[/PDF] This site is using cookies under cookie policy . q /Resources<< /Meta348 362 0 R /F3 17 0 R /Length 16 ET q /Type /XObject << stream stream stream 129 0 obj /Length 69 /Type /XObject Q endobj Q /Subtype /Form endobj 294 0 obj Q endobj /FormType 1 >> /Leading 349 /FormType 1 1.007 0 0 1.007 654.946 347.046 cm q /Resources<< /Type /XObject /Meta194 208 0 R 0 g 1 i endstream endobj stream 1.007 0 0 1.006 411.035 690.329 cm stream 299 0 obj /Length 16 /Subtype /Form q 0 G 1 g >> endstream /Matrix [1 0 0 1 0 0] /Resources<< /Type /XObject /Matrix [1 0 0 1 0 0] q saugatpandey635 saugatpandey635 22.09.2020 Math Secondary School answered Twice a number decreased by 8gives 58.
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